Hi - I'll do a bit of cut and paste and try ot make sense. the basic issue is that measuring current per se is very difficult to do in aquaria, so people use turnover as a rough approximation, but as you are seeing it is a rough approximation.
Turn over : From what I understand turn over is the amount of water that leave the tank and re-enter after passing through come kind of a filter or water that just leave the tank and re-enter the tank <<AND/OR the amount of water moved by a powerhead>>
Flow rate: This is the actual water movement in your tank. <<Umm not really thinking about it, though it could be. As a rate it is a function of time so you could describe flow rate as a current i.e. 30 centimetres persecond. Normally though it is the amount of water a device shifts, i.e. 2000 litres per hour>>
Suppose, you have 55 gallon tank with canister filter that is rated at say 2750 GPH <<Some cannister!>>. This mean that you have 50 time turn over. Water leave the tank and re-enter at rate of 2750 GPH … 50 times the volume of the water. This doesn’t necessarily mean that entire volume of water in your tank is turned over 50 times. It simply mean 2750 gallon of water moved through the system (disregard head loss or any other loss … theoretically). But my tank may have many dead spots <<Indeed. Maximising water movement to avoid dead spots is not always straightforward>>.
To prevent dead spots you place a few power heads in the tank. To me this flow rate … how fast the water is moving … i.e. current. <<You could still have dead spots tho' even if one part of the tank has a hideously high current>>
So in my mind, water simply turning over number of times does create a current within the tank. Having powerhead rated at 2750 GPH alone isn’t enough either. You must strike balance between flow rate and turn over. Substitute the word current for flow rate and I thnk this will be clearer>>
Now to my 70 gal tank. I have pump from the sump rated at 1200 GPH and fluval canister filter rated at 317GPH. This is about 21 times turn over (theoretically). But only have couple of 505 powerhead on either end of the tank. If I were to place my hand on the middle of the tank, I feel absolutely no current. <<Typical>>This is why I feel that my tank as inadequate flow rate, yet enough turn over. Now, I have an extra pump that I can use to create a close loop. But this would only increase turn over and not increase flow rate or remove dead spots.<<Well set it up right>> What is my best option?
<<If you want to get serious about water flow you have options. But remember one thing - squeezing mucho water out of a little hole, even at high flow rates, will not give you good current. The stream is narrow, high velocity and terribly turbulent and typically will have dissipated to not much after 20 centrimetres from the exit. Compare to the stream from a Tunze or Seio - big propellors, big exit holes, lower velocities leaving the pump, but as the 'stream' of water is wider and less turbulent it trvels much, much further. Trad Powerheads were NOT designed to provide currents, in tank flow - they were designed to feed things like powered UGF's UV's, skimmers et al, and their nonoptimised propellor/impellor design reflects this.
Ditto with the closed loop - if you pump all the out flow from one little hole it will be much less effective than more ,larger outlets.
The semi exception to this are eductors, and your tank isn't big enough for an eductor I think, though there are mini version available. Google eductor or use wikipedia for a description.